How many grams of carbon monoxide are needed to react with an excess of iron (iii) oxide to produce 198.5 grams of iron? fe2o3(s) + 3co(g) > 3co2(g) + 2fe(s) show all work step by step !

The  grams of  carbon   monoxide  that are needed to react   is  148.68 grams

  calculation

Step 1: find the   moles of iron

 moles =mass÷  molar mass

from periodic table the molar mass  of Fe  is 56 g/mol

= 198.5 g÷ 56 g/mol =3.54 moles

Step 2: use the mole  ratio  to determine the  moles  of  carbon monoxide(Co)

that is from  given equation Co : Fe  is 3:2  therefore the  moles of Co

= 3.54 x 3/2 = 5.31  moles

Step 3 : find mass of CO

mass = moles ×  molar mass

from periodic table  the molar mass  of Co = 12+16 = 28 g/mol

mass is therefore = 5.31 moles × 28 g/mol = 148.68  grams