Chemistry, 29.06.2019 03:00 fahad7007

50 ! a section of the periodic table is shown below: a portion of the first two columns of the periodic table is shown. column one from reads 11 sodium 22.990 and 19 potassium 39.098. column two reads 12 magnesium 24.305 and 20 calcium 40.078. which of the following statements is true? k is more reactive than ca because k has to gain only one electron to complete its outermost shell. k is more reactive than ca because k has to lose only one electron to complete its outermost shell. mg is more reactive than na because mg has to lose only one electron to complete its outermost shell. mg is more reactive than na because mg has to gain only one electron to complete its outermost shell.

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Answer from: ashleypere99

The answer is: K is more reactive than Ca because K has to lose only one electron to complete its outermost shell.

Potassium is a chemical element with atomic number 19 (number of electrons is 19).

Electron configuration of potassium is: ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.

Potassium is the alkali metal and has a single valence electron in the outer electron shell.

Periodic law is the arrangement of the elements in order of increasing atomic number.

For example all alkaline metals (I group of periodic table, Na, K, Cs...) loose one electron in chemical reaction and react vigorously with water.

Reactivity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity).

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

Alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons (one electron, earth alkaline metals (right next to alkaline metals) have higher ionization energy than alkaline metals, because they have two valence electrons.

Answer from: Quest

explanation:

Answer from: Quest

$\frac{239}{94}pu+\frac{1}{0}n ====> \frac{y}{z}x+\frac{134}{54}xe+3\frac{1}{0}$

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137 subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54 subtract 54 from both sides.

40 = z

answer

$\frac{103}{40}x=\frac{103}{40}zr$

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