6. balance the following equations (3 points)a. fecl3 + naoh  fe(oh)3 + naclb. c2h2 + o2 -- co2 + h2oc. fe2o3 + h2 -- fe + h2o

The answer is

a.  FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

b. 2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

c. Fe2O3 + 3 H2 = 2 Fe + 3 H2O

To balance equations you basically have to make sure each element has an equal amount or number on each side of the equation. If you need more help understanding this, feel free to ask.

:)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml