What is the poh of a 7.9 x 10 ^-4 m oh- solution? poh= ?

pOH is defined as -log([OH-]).

pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1

Hope this helps!

pOH of the given hydroxide ion concentration is 3.10

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:

We are given:

Hydroxide ion concentration,

Putting values in above equation, we get:

Hence, pOH of the given hydroxide ion concentration is 3.10