Which of the following would represent a single displacement reaction between potassium bromide (k^+br^-) and iodine (i), which forms iodide ( options: kbr + i -> k + ibr kbr + i -> kbr + i kbr + i -> ki + br

Option : KBr + I -> KBr+I

Explanation:

Single-replacement reaction or single displacement reactions are a type of chemical reactions in which a whole compound reacts with an element in such a way that the element takes place of one of the compound's own elements and sets it free.

If we talk about KBr and I displacement reaction is not possible among these because Iodine is less reactive than Bromine that is why it will not react with KBr or replace Br.

                       KBr + I -> KBr+ I

Potassium Bromide + Iodine -> Potassium bromide + Iodine

Hope it help!

2b2t

explanation:

2b2t

gold is my favorite solid.