A72.84 g sample of ba(oh)_2ba(oh) 2 is dissolved in enough water to make 1.700 liters of solution. how many ml of this solution must be diluted with water in order to make 1.000 l of 0.100 m ba(oh)_2ba(oh) 2

Answer : 399.8 ml of solution must be diluted with water.

Solution : Given,

Mass of = 72.84 g

Volume of solution = 1.7 L

Molarity of water = 0.1 mole/L

Volume of water = 1 L

First we have to calculate the molarity of solution.

Formula used :

where,

M = molarity of solution

= mass of

= molar mass of

= volume of solution

Now put all the given values in this formula, we get

Now we have to calculate the volume of solution.

Formula used :

where,

= molarity of solution

= molarity of water

= volume of solution

= volume of water

Now put all the given values in this formula, we get

By rearranging the term, we get

      (1 L = 1000 ml)

Therefore, 399.8 ml of solution must be diluted with water.

more info ? ? i don't understand what the question is

explanation:

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !