Above what fe2 concentration will fe(oh)2 precipitate from a buffer solution that has a ph of 8.18? the ksp of fe(oh)2 is 4.87×10-17.

The solubility equilibrium is represented by the following reaction:

Fe(OH)2 (s) ↔ Fe2+(aq) + 2OH-(aq)

Ksp = [Fe2+][OH-]²(1)

It is given that: pH = 8.18

Now, pH + pOH = 14

pOH = 14 - 8.18 = 5.82

[OH-] = 10^-pOH = 10^-5.85 = 1.51*10⁻⁶M

From eq(1)

[Fe2+] = Ksp/[OH-]² = 4.87*10⁻¹⁷/(1.51*10⁻⁶)² = 2.14*10⁻⁵M

Ans: [Fe2+] = 2.14*10⁻⁵M

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation: