How is it possible for 10 grams of methane fuel to burn in emit 27 grams of carbon dioxide discuss whether or not this reaction obeys the law of conservation of mass

Answer : It is possible for 10 grams of methane fuel to burn and emit 27 grams of carbon dioxide because it is following the law of conservation of mass.

Solution : Given,

Molar mass of = 16 g/mole

Molar mass of = 44 g/mole

The Net balanced equation for this reaction is,

First we have to calculate the moles of .

Moles of

Moles of = 0.625 moles

From the balanced equation we conclude that

1 mole of gives 1 mole of

0.625 moles of gives of

Moles of = 0.625 moles

Now we have to calculate the Mass of .

Mass of = Moles of × Molar mass of = 0.625 moles × 44 g/mole = 27.5 g

Mass of = 27.5 g

Law of conservation of mass : In the balanced chemical reaction, the number of atoms on each side of the equation must be equal.

Therefore, it is possible for 10 grams of methane fuel to burn and emit 27 grams of carbon dioxide because it is following the law of conservation of mass.

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