How many grams of water (h2o) are produced if i burn 4 moles of octane (c8h18) in excess oxygen? 2c8h18 + 25o2  16co2 + 18h2o

25.7 mol

From the balanced reaction, 2 mol of Octane produces 18 mol of Water.

Find the moles of Octane you are reacting.

moles of Octane = mass of Octane/ molar mass = 325g/ 114.23 g/mol = 2.85 mol.

Since Oxygen is in excess, limiting reagent is Octane.

2 mol Octane produces 18 mol Water.

1mol Octane produces 9 mol Water.

Therefore, 2.85 mol Octane will produce Water = 2.85 mol Octane x 9 mol Water/ 1mol Octane

= 25.7 mol

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.

idk what is it? is this a question that you know the answer or u dont