Use bond energies from table 10.3 in the textbook to estimate the enthalpy change (δh) for the following reaction. c2h2(g)+h2(g)→c2h4(g) δh=?

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of  C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

= {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

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