What would be the final volume (in ml) of the aqueous potassium fluoride which was prepared by dissolving 8.0 g of potassium fluoride in an appropriate volume of water to give a 0.89 m aqueous solution?

0.15 L

Explanation:

Step 1. Calculate the moles of KF.

Molar mass = 58.10 g/mol

Moles of KF = 8.0 × 1/58.10  

Moles of KF = 0.138 mol KF

Step 2. Calculate the volume of KF

c = n/V                  Multiply both sides by V

V = 0.138 × 1/0.89  

V = 0.15 L

2b2t

explanation:

2b2t