Calculate the heat of reaction for the following reaction: h2(g)+cl2(g)(g) round your answer to the nearest .

Given reaction:

H2(g) + Cl2(g) → 2HCl(g)

Formula:

Heat of the reaction is the enthalpy change given as:

ΔHrxn = ∑nΔH°f(products) - ∑nΔH°f(reactants)

          = [2ΔH°f(HCl(g))] - [ΔH°f(H2(g)) + ΔH°f(Cl2(g))]

          = [2(-92.31)] - [0 + 0] = -184.62 kJ/mol

The heat of the reaction is -184.62 kJ/mol

b

explanation:

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