How many particles are present in 15.0 g of ccl4? (show work : ))

5.86*10^22particles

Explanation:

First obtain the molar mass of tetrachloromethane then compare the given mass in the question with Avogadro's number as shown in the solution. Note that the Avogadro's number is the number of particles contained by one mole of all substances at standard temperature and pressure. According to Avogadro, at the same temperature and pressure, one mole of all substances contain equal number of molecules

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3