What is the limiting reactant when 5.6 moles of aluminum react with 6.2 moles of water? unbalanced equation: al + h2o → al2o3 + h2show, or explain, all of your work along with the final answer.

The limiting  reactant  when 5.6  moles   of aluminium react  with  6.2  moles   of water   is

      water( H2O)

      Explanation

The  balanced    equation is as below

2 Al +3 H2O  →  Al2O3  +3 H2

The mole ratio  of Al :Al2O3  is 2:1  therefore  the  moles  of  Al2O3

  = 5.6 x1/2  =  2.8  moles

The   mole  ratio  of H2O: Al2O3  is 3:1 therefore  the  moles  of Al2O3  produced

                 = 6.2  x1/3= 2.067  moles

since  H2O  yield  less  amount  of Al2O3 ,  H2O   is  the limiting reagent.

Given:

Moles of Al = 5.6 moles

Moles of H2O = 6.2 moles

To determine:

The limiting reagent

Explanation:

The chemical reaction is-

2Al + 3H2O → Al2O3 + 3H2

- Based on stoichiometry; 2 moles of Al forms 1 mole of Al2O3

Therefore, 5.6 moles of Al would give: 5.6 Al * 1 Al2O3/2 Al = 2.8 moles Al2O3

-Similarly; 3 moles of H2O forms 1 mole of Al2O2

Therefore, 6.2 moles of H2O would give: 6.2 H2O * 1 Al2O3/3 H2O = 2.07 moles Al2O3

Ans: Since the amount (moles) of Al2O3 formed from H2O is less, water is the limiting reagent.

b) mutualism

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