Determine the mass of chloride (mw = 35.45 g/mol ) in grams present in 100 ml of a 0.325 m solution of aqueous ticl3 (titanium(iii) chloride).

 The  mass   chloride is  3.456 grams

 calculation

 Step:1 calculate the moles of TiCl3

moles = molarity  x  volume  in liters

volume in liters = 100 ml /1000 =  0.1 L

molarity = 0.325  M  =  0.325  mol / L

moles  is therefore  =  0.1 L x  0.325  mol /L = 0.0325   moles

step 2: find the moles of Cl

since there is  3  atoms of  cl in TiCl3  the moles of Cl

= 3 x 0.0325 =0.0975 moles

Step 3:  calculate  mass  of cl

 mass= moles  x molar mass

=0.0975 moles x 35.45 g/mol = 3.456 g

a is the correct answer