What are the oxidizing agent and the reducing agent in this chemical equation? 3fes + 8hno3 → 3feso4 + 8no + 4h2o

The oxidizing agent is one which itself gets reduced and oxidizes other

Reduction : in this process the element accepts electron and gets reduced

Reducing agent is one which itself gets oxidized and reduces other

Oxidation : in this process the element loses electron and gets oxidized

Here the oxidation number of Sulphur change  from -2 (FeS) to +6 (FeSO4) so it is oxidized and thus it is the reducing agent

The oxidation number of nitrogen changes from +5 (HNO3) to +2 (NO) thus it is reduced and thus it is the oxidizing agent

The reducing agent is FeS and the oxidizing agent is

Explanation:

Oxidizing agent is defined as the agent which oxidizes the other substance and itself gets reduced. It undergoes reduction reaction which means it gains electrons and the oxidation state of the substance gets reduced.

Reducing agent is defined as the agent which reduces the other substance and itself gets oxidized. It undergoes oxidation reaction which means it looses electrons and the oxidation state of the substance is increased.

For the given chemical equation:

On reactant side:

Oxidation state of Iron = +2

Oxidation state of Sulfur = -2

Oxidation state of oxygen = -2

Oxidation state of hydrogen = +1

Oxidation state of nitrogen = +5

On product side:

Oxidation state of Iron = +2

Oxidation state of Sulfur = +6

Oxidation state of oxygen = -2

Oxidation state of hydrogen = +1

Oxidation state of nitrogen = +2

As, oxidation state of Sulfur is increasing from -2 to +6, it is loosing electrons and thus it is undergoing oxidation reaction and FeS is considered as a reducing agent. And the oxidation state of Nitrogen in reducing from +5 to +2, it is gaining electrons and thus it is undergoing reduction reaction and is considered as an oxidizing agent.

Thus, The reducing agent is FeS and the oxidizing agent is

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2