I’m trying to find the molarity of h2so4 in this calculation. i attempted it but i still need someone to check my work. i used 10.00 ml of h2so4 and the volume added to it was 24.97 ml of the 0.0924m naoh solution. the equation is 2naoh + h2so4 -> 2h2o + na2so4, so i’m aware 1 mol of h2so4 is 2 mol naoh. what i tried: 0.0924 mol/l x 0.02497 l= 0.002307 mol naoh x 1 mol h2so4/2 mol naoh= 0.001156 mol h2so4 0.0011536 mol h2so4/0.01000 l h2so4= 0.1154m h2so4 am i doing this right?