Which of the following correctly compares the radii of na and na+? a. na has a smaller radius than na+ because na has expanded its electron cloud. b. na has a larger radius than na+ because na has lost its outermost energy shell. c. na has a smaller radius than na+ because na+ has expanded its electron cloud. d. na has a larger radius than na+ because na+ has lost its outermost energy shell.

  The statement   that correctly compares  the radii  of Na and Na+ is

Na  has a larger  radius than Na+  because Na+   has  lost  its  outermost energy  shell  ( answer D)

  Explanation

sodium (Na)  is in atomic  number  11  and hence  has  1s2 2s2 2p6 3s1  or [Ne] 3s1   electron  configuration.

Sodium   metal (Na) loses    1 electron  in the  outermost shell  to  form   Na+  with 1s2 2s2 2p6  electron configuration.

Therefore  Na   has  larger atomic radius   than Na+ because      Na+   is  formed  when   1 electron is lost  by  Na atom.

 In addition the  nuclear  charge   of Na+   is greater  than that  of Na.   This  make the valence electron of Na+  to attracted  closer to the nucleus  which  make the  atomic radius of Na+ to be  smaller than that  of Na.

D. Na has a larger radius than Na+ because Na+ has lost its outermost energy shell.

Which of the following correctly compares the radii of Na and Na+? (5 points)

A. Na has a smaller radius than Na+ because Na has expanded its electron cloud.

B. Na has a larger radius than Na+ because Na has lost its outermost energy shell.

C. Na has a smaller radius than Na+ because Na+ has expanded its electron cloud.

D. Na has a larger radius than Na+ because Na+ has lost its outermost energy shell.

Explanation:

I just took the test and D. Na has a larger radius than Na+ because Na+ has lost its outermost energy shell, is the correct answer!

Good Luck!!

"the periodic table is arranged in order of atomic number."

c (diamond),

sio2 (quartz)