When an electron of a hydrogen atom travels from n=4 to n=2, a photon of energy 4.165•10^-19 joules is released. calculate the wavelength associated with this radiation.

Energy level diagrams and the hydrogen atom ... Consider the photon emitted when an electron drops from the n=4 to the n=2 state to the photon emitted

Energy of photon, E = hν    

Frequency of photon,  

Thus, energy of photon,  

Therefore, 4.165 × 10-19 joules =  

λ  = 4.77 × 10-7 meters

The frequency of a photon having energy of 4.165 × 10-34 joules is 4.77 × 10-7 meters.

Explanation:

Plato

i think its 5049.

i hope this !