A250. ml sample of 0.3m hcl is partially neutralized by the addition of 100. ml of 0.25m naoh. find the concentration of hydrochloric acid in the resulting solution.

- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

= 0.075 mol HCl

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the resulting solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution =

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

dynamic equilibrium is the answer.

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