The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Answer :  The solubility of this compound in g/L is .

Solution : Given,

Molar mass of = 114.945g/mole

The balanced equilibrium reaction is,

At equilibrium                         s       s

The expression for solubility constant is,

Now put the given values in this expression, we get

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

Therefore, the solubility of this compound in g/L is .

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

that tool would be a compass