An element a combines with fluorine to form an ionic compound having the formula af3. what is the formula of the ionic compound formed between iodine and a?

Here we have to determine the formula of the ionic compound formed between a and iodine.

The ionic compounds are those which remains in ionic state in its solution phase. The formula of the compound aF₃ which reveals the element a is trivalent i.e. a³⁺. It will remain in ionic state as follows: aF₃ → a³⁺ + 3F⁻.

As the element a is trivalent thus with iodine also it will combine like fluorine  (as both belongs to the same halogen group). The formula of the compound will be aI₃ and it will be ionic in nature. The ions will be aI₃ → a³⁺ + 3I⁻.

Thus the formula of  the ionic compound between a and iodine is determined.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2