1. what is the frequency in hertz of a photon that has a wavelength of 5.78 x 104 m? 2. calculate the wavelength of a wave that has a frequency of 22.4 mhz. 3. what is the frequency in hertz of a photon that has a wavelength of 67.9 m? 4. calculate the wavelength of a wave that has a frequency of 34.66 hz. 5. what is the frequency in hertz of a photon that has a wavelength of 9.98 mm?

Answer :

Solution For 1 :

Given,

wavelength =

Speed of light =

Formula used :

          .............(1)

= frequency

= wavelength

c = speed of light

Now put all the given values in above formula, we get

=  

(1Hz = 1 per second)

Therefore, the frequency of a photon in hertz is .

Solution For 2 :

Given,

Frequency =      

Speed of light =

Now put all the given values in above formula (1), we get

Therefore, the wavelength of a wave is 13.38 m.

Solution For 3 :

Given,

wavelength =

Speed of light =

Now put all the given values in above formula (1), we get

=

Therefore, the frequency of a photon in hertz is .

Solution For 4 :

Given,

Frequency =

Speed of light =

Now put all the given values in above formula (1), we get

Therefore, the wavelength of a wave is .

Solution For 5 :

Given,

wavelength =      (1 m  = 1000 mm)

Speed of light =

Now put all the given values in above formula (1), we get

=

Therefore, the frequency of a photon in hertz is .

43.452

step-by-step explanation:

284 times .153 = 43.452

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j