Agas that exerts a pressure of 2.15 atm in a container with a volume of 0.0900 l will exert a pressure of atm when transferred to a container with a volume of a 4.75 l

Given:

Initial pressure exerted by the gas P1 = 2.15 atm

Initial volume of the container V1 = 0.0900 L

Final volume of the new container V2 = 4.75 L

To determine:

Pressure P2 exerted by the gas in the new container

Explanation:

The ideal gas equation is given as-

PV = nRT

where n = moles of the gas

R = gas constant and T = temperature

Since the values of n, R, T do not change when the gas is transferred to the new container, we have the relation

PV = constant

or, P1V1 = P2V2

P2 = P1V1/V2 = 2.15 * 0.0900/4.75 = 0.041 atm

Ans: The pressure exerted by the gas in the new container is 0.041 atm

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.