What size container do you need to hold 0.0459 mol of n2 gas at stp

The size of the container needed is 1,03 liters

Explanation:

We use the formula PV=nRT. The STP conditions correspond to 1 atm of pressure and 273 K of temperature.

PV=nRT V=(nRT)/P

V= (0,0459 mol x 0,082 l atm/ K mol x 273K)/1 atm= 1,0275174 liters

answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.