How many ml of a 0.216m aqueous solution of barium sulfide must be taken to obtain 12.5 grams of the salt?

Hey there!:

Molar mass BaS => 169.39 g/mol

Number of moles:

n = mass of solute / volume ( L )

n = 12.5 / 169.39

n = 0.0737 moles of BaS

Volume of solution:

M = n / V

0.216 = 0.0737 / V

V = 0.0737 / 0.216

V = 0.3412 L

Now converts the volume to mL :

0.3412 L * 1000 => 341.2 mL

Hope that helps!

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.