How many moles of pb(so4)2 are equivalent to 156.5 g of pb(so4)2 (mw. 399.34 g/mol)?

0.392 moles of Pb(SO4)2 are equivalent to 156.5 g of Pb(SO4)2.

HOW TO CALCULATE NUMBER OF MOLES:

That is;

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The relation of this question can be written as follows:

X moles of Pb(SO4)2 = 156g of Pb(SO4)2

We already know the Molecular weight of Pb(SO4)2 is

This can be found from the atomic mass of each element of the Periodic Table.

But, we need to make a change of units from g/moles to moles, and we can do it using the following formula:

We have:

grams of Pb(SO4)2=156.5 g

molecular weight of Pb(SO4)2= 399.34 g/moles

Now we only have to substitute the values, being careful with the units:

Finally :

0.3918 moles of Pb(SO4)2 are equivalent to 156.5 g of Pb(SO4)2

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explanation:

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.