How many liters of hydrogen gas is produced at 298 k and 0.940 atm if 4.00 moles of hydrochloric acid react with an excess of magnesium metal?

The number of liters   of hydrogen  gas that is  produced at 298 k  and  0.940 atm  if  4  moles of HCL  reacted  with an excess of  magnesium  metal  is   52.05 L

 calculation

step 1: calculate the number of moles of H2

Step 2:  use the ideal gas  equation to  calculate  the volume of  hydrogen

       p(pressure)=  0.940  atm

      V( volume)= ?

    n(moles)=  2  moles

  R( gas constant)=  0.0821  atm.l/mol.k

 T(temperature)=  298 k

         V  is therefore=nRT/P

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explanation:

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer