Ionic bonds generally form when the bonded elements have a difference in electronegativity greater than 1.5 to 1.7. subtract the electronegativities for the following pairs of elements and predict whether they form ionic bonds. electronegativity difference of na and f: yes no

Yes, sodium and fluorine form ionic bonds.

Explanation:

Electronegativity of sodium (Na) is 0.93.

Electronegativity of fluorine (F) is 3.98.

Electronegativity difference of Na and F will be calculated as follows.

   Electronegativity difference = Electronegativity of F - Electronegativity of Na

                                                   = 3.98 - 0.93

                                                   = 3.05

Thus, difference in electronegativity greater than 1.5 to 1.7, hence, bond between sodium and fluorine is ionic.