If the temperature remains constant and the initial pressure is 101.3 kpa then what is the new pressure reading when the volume is doubled

             The pressure will decrease by half.

Data Given:

                  P₁  =  101.3 kPa  

                  V₁  =  X

                  V₂  =  2X

                   P₂  =  ??

Let us suppose the initial volume is 5 L and the final volume when doubled is 10 L. Then According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂     (1)

Solving equation 1 for P₂,

                                     P₂  =  P₁ V₁ ÷ V₂

Putting values,

                                     P₂  =  (101.3 kPa × 5 L) ÷ 10 L

                                     P₂  =  50.65 kPa

          As the volume is doubled, the pressure is decreased from 101.3 kPa to 50.65 kPa or it has decreased by half.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j