Using orbital notation, diagram the formation of an ionic bond between aluminum and fluorine.

In order to make the ionic compound between two given elements, one should first decide to select which element an an anion (containing negative charge) and which element as cation (containing positive charge).

In given statement Fluorine being more electronegative (4.0) than Aluminum (1.61) will bear negative charge while, Aluminium will attain positive charge.

Formation of F⁻ Ion:

                                The atomic number of Fluorine is 9. Hence in neutral state it will carry 9 electrons with following electronic configuration,

                                       1s², 2s², 2px², 2py², 2pz¹

Therefore, in order to complete its octet, Fluorine will accept one electron as,

                                       1s², 2s², 2px², 2py², 2pz²

Or,

                                       1s², 2s², 2⁶

Or,

                                      F⁻  =  [He], 2s², 2⁶

Formation of Al³⁺ Ion:

                                   The atomic number of Aluminium is 13. Hence in neutral state it will carry 13 electrons with following electronic configuration,

                                       1s², 2s², 2⁶, 3s². 3p¹

Therefore, in order to complete its octet, Aluminium will loose three electron as,

                                       1s², 2s², 2⁶

Or,

                                      Al⁺³  =  [He], 2s², 2⁶

Formation of AlF₃:

                                 In order to have a neutral ionic compound, three ions of Fluoride containing -1 charge each will bond with a single cation of Aluminium containing +3 charge. Hence,

                                            3 F⁻ +  Al⁺³  =  AlF₃

what are the two models

explanation:

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.