If 1200 j of heat were absorbed by a 25 g block of iron, by how much would the temperature of the iron increase?

m = mass of the block of iron = 25 g

Q = heat absorbed by the block of iron = 1200 J

ΔT = increase in the temperature of iron due to heat absorbed = ?

c = specific heat of block of iron = 0.450 J/(g C)

Heat absorbed by the block of iron is given as

Q = m c ΔT

inserting the values in the above formula

1200 = 25 (0.450) ΔT

1200 = (11.25) ΔT

ΔT = 1200/11.25

ΔT = 106.67 C

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer