Calculate the kelvin temperatures of the water and record your answers in the data table.

Answer : The temperature of boiling water of part A (in Kelvin) = 373.15 K

The temperature of boiling water of part B (in Kelvin) = 372.15 K

The final temperature of cooling water of part A (in Kelvin) = 296.15 K

The final temperature of cooling water of part B (in Kelvin) = 280.15 K

Solution : Given,

The temperature of boiling water of part A =

The temperature of boiling water of part B =

The final temperature of cooling water of part A =

The final temperature of cooling water of part B =

Conversion of into Kelvin.

By using this conversion, we get

The temperature of boiling water of part A = = 100 + 273.15 = 373.15 K

The temperature of boiling water of part B = = 99 + 273.15 = 372.15 K

The final temperature of cooling water of part A = = 23 + 273.15 = 296.15 K

The final temperature of cooling water of part B = = 7 + 273.14 = 280.15 K

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.