Asweetened ice tea beverage of 355ml contains 43.0 g of sucrose (sugar). calculate the molarity of sucrose in the drink. sucrose: c12h22o11 molar mass kf sucrose= 342.3 g/mol

Hey there!:

Molar mass sucrose = 342.3 g/mol

Number of moles:

n = m / mm

n = 43.0 / 342.3 => 0.1256 moles of sucrose

Volume in liters of solution:

355 mL / 1000 => 0.355 L

Therefore:

M = n / V

M = 0.1256 / 0.355

= 0.353 M

Hope that helps!

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2