How many grams of xef6 are required to react with 0.579 l of hydrogen gas at 4.46 atm and 45°c in the reaction shown below?

Hey there!:

Temperature in kelvin : 45 + 273 => 318 K

Number of moles H2:

p * V = n * R * T

4.46 * 0.579 = n * 0.082 * 318

2.58234 = n * 26.076

n = 2.58234 / 26.076

n = 0.09903 moles of H2O

Given the reaction:

XeF6(s) + 3 H2(g) → Xe(g) + 6 HF(g)

Molar  mass XeF6 = 245.3 g/mol

0.09903 mol H2O *  ( 1 mol XeF6 / 3 mol H2 ) * 245.3

= 8.09 g of XeF6

Hope that helps

i'm assuming that the correct answer is indeed the first one/ "a"..

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates