Acompound is found to contain 63.65% nitrogen and 36.35% oxygen by mass. what is the empirical formula for this compound

You will change the percent to gram

N = 63.65 % => 63.65 g

O = 36.35 % => 36.35 g

The formula for this question is mole = mass / Molar mass

  N = 63.65 g / 14.01 g/mol = 4.54 mol

  O = 36.35 g / 16.00 g/mol = 2.27 mol

Take the smallest number in 2 element and divide them.

  N = 4.54 / 2.27 = 2

  O = 2.27 / 2.27 = 1

The empirical formula is N2O

Hope this help!