How much work (in j) is involved in a chemical reaction if the volume decreases from 5.35 to 1.55 l against a constant pressure of 0.829 atm?

- work = 319 J

Solution:- The volume of the gas decreases from 5.35 L to 1.55 L.

 = -3.80 L

external pressure is given as 0.829 atm.

where w is representing work.

Let's plug in the values and calculate pressure-volume work:

w = 3.15 atm.L

We need to convert atm.L to J.

1 atm.L = 101.325 J

So,

= 319 J

So, 319 J of work is involved in a chemical reaction. Positive work means the work is done on the system.

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