How many liters of water vapor can be produced if 8.9 liters of methane gas (ch4) are combusted, if all measurements are taken at the same temperature and pressure? show all of the work used to solve this problem. ch4 (g) + 2o2 (g) yields co2 (g) + 2h2o (g)

The normal condition of the mole of a gas is 22.44L.

The volume of CH4 = 8.9L

To get the number of moles we get,

8.9 / 22.44 = 0.397 moles.

The ratio of CH4 : H2O = 1: 2

The mole of water is 0.379 × 2 = 0.794 moles.

While we convert it into liters it will be

0.794 × 22.414 = 17.80L

The answer is 17.80 liters of water vapour which will be produced.

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)