Consider the reaction.at equilibrium, the concentrations of the different species are as follows.[h2o] = 0.077 m[cl2o] = 0.077 m[hclo] = 0.023 mwhat is the equilibrium constant for the reaction at this temperature? 0.0890.263.911

0.089.

Explanation:

Cl₂O + H₂O ⇄ 2HClO,

Kc = [HClO]²/[Cl₂O][H₂O].

[H₂O] = 0.077 M , [Cl₂O] = 0.077 M , [HClO] = 0.023 M.

∴ Kc = [HClO]²/[Cl₂O][H₂O] = (0.023 M)²/(0.077 M)(0.077 M) = 0.08922 ≅ 0.089.

i have a feeling this is a gay person trolling to make straights look bad.

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