Acertain quantity of gas occupies a volume of 0.1 l when collected over water at 288 k and a pressure of 0.92 bar. the same volume of gas occupied a volume 0.85 l at s. t.p in dry conditions. calculate the aqueous tension at 288k.

We know that

Ptotal = Pdry gas + Pwater  = Pdry gas + aqueous tension [Dalton's law]

Ptotal = 0.92 bar

So

Aqueous tension = 0.92 - Pdry gas

Now moles of gas is constant

We can use ideal gas equation

PV = nRT

P1V1 / T1 = P2V2 /T2 [n and R constant]

P1 X 0.1 / 288 = 1 X 0.085 / 273 .15 = 0.896

so aqueous tension = 0.92 - 0.896 = 0.024 bar

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