What is the mass (in g) of carbon in a sample of acetone, ch3coch3, which also contains 2.45 g of hydrogen?

Answer is: the mass of the carbon is 14.57 grams.

m(H) = 2.45; mass of hydrogen in sample of acetone.

n(H) = m(H) ÷ M(H).

n(H) = 2.45 g ÷ 1.01 g/mol.

n(H) = 2.425 mol; amount of hydrogen.

From molecular formula of acetone: n(C) : n(H) = 3 : 6 (1 : 2).

n(C) = 2.425 mol ÷ 2.

n(C) = 1.212 mol; amount of carbon in the sample.

m(C) = n(C) · M(C).

m(C) = 1.212 mol · 12.01 g/mol.

m(C) = 14.57 g.