In a 0.100 m hf solution, the percent dissociation is determined to be 9.5%. calculate the ka for hf based on this data.

Answer : The dissociation constant (Ka) = 9.025 ×

Solution :  Given,

                Concentration HF solution = 0.100 M

                 % Dissociation = 9.5 %

The equation for dissociation of HF is :

The Ka expression for HF is :

       ............. (1)

Step 1 : we find the by using the concentration and % dissociation.

  = Concentration HF solution ×  % Dissociation

  = 0.100 M × = 9.5 × M

Step 2 : For , the concentration of   is equal to the  . From the above equation the stoichiometry of   and is 1:1.

Therefore,

=    = 0.100 M × =    =  9.5 × M

Now, put all the values in equation (1), we get

           = 9.025 ×

im not exactly sure but i think its b!

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.