Zinc reacts with hydrochloric acid according to the reaction equation how many milliliters of 3.50 m hcl(aq) are required to react with 2.25 g of zn(s)?

The balanced chemical reaction of Zn with HCl is

Zn  + 2HCl  --> ZnCl2  + H2(g)

So here one mole of Zn reacts with two moles of HCl

Moles of Zn = mass of Zn / atomic mass of Zn = 2.25 / 65.38 = 0.0344

so moles of HCl reacted = 2 X moles of Zn = 2 X 0.0344 = 0.0688

Moles  = molarity X volume

Therefore

Volume = moles / molarity = 0.0688 / 3.50 = 0.019657 L = 19.657 mL

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explanation:

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