Part a what is the concentration of k+ in 0.15 m of k2s? express your answer to one decimal place and include the appropriate units. 0.3 m submithintsmy answersgive upreview part correct part b if cacl2 is dissolved in water, what can be said about the concentration of the ca2+ ion? if is dissolved in water, what can be said about the concentration of the ion? it has the same concentration as the cl− ion. its concentration is half that of the cl− ion. its concentration is twice that of the cl− ion. its concentration is one-third that of the cl− ion. submithintsmy answersgive upreview part correct part c a scientist wants to make a solution of tribasic sodium phosphate, na3po4, for a laboratory experiment. how many grams of na3po4 will be needed to produce 650. ml of a solution that has a concentration of na+ ions of 1.30 m ?

1. Concentration K⁺ = [K⁺] = 0.3 M

2. Ca²⁺concentration is half that of the Cl⁻ ion.

3. 45,838 grams of Na₃PO₄ will be needed

Stokiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.

Reaction equations are chemical formulas for reagents and product substances

Reaction coefficients are numbers in the chemical formula of substances involved in the reaction equation. Reaction coefficients are useful for balancing reagents and products.

The reaction coefficient shows the ratio of the number of moles or molecules of the reacting substance

The ionization reaction is the reaction of the decomposition of a substance into its ions when the substance is dissolved in water.

Molarity (M)

Molarity shows the number of moles of solute in every 1 liter of solution.

Where

M = Molarity

n = Number of moles of solute

V = volume of the solution

K₂S(aq) ----> 2K⁺ (aq) + S²⁻ (aq)

Comparison of reaction coefficients = mole ratio = concentration ratio for the same volume, so

K₂S coefficient: coefficient 2K⁺ = 1: 2

[K⁺] = 2. [K₂S]

[K⁺] = 2. 0.15 M

[K⁺] = 0.3 M

CaCl₂ -> Ca²⁺ + 2Cl⁻

Same as the explanation in point 1:

coefficient Ca²⁺: coefficient Cl⁻= 1: 2

so that

 [Ca²⁺] = 1/2 [Cl⁻]

[Ca²⁺] half of the concentration [Cl⁻]

Na₃PO₄ ---> 3Na + + PO₄³⁻

[Na₃PO₄] = 1/3. [Na +]

[Na₃PO₄] = 1/3. 1.3

[Na₃PO₄] = 0.43 M

then the number of moles is

mol = M. vol

mole = 0.43. 0.65 L

mole = 0.2795

 So that its mass:

molar mass of Na₃PO₄ = 164 g / mol

mass = mole. molar mass

mass = 0.2795. 164

mass = 45,838 grams

grams of hydrogen

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grams of calcium chloride

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sample of H₃PO₄ solution

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Keywords: ionization, molar mass, mole, mass, Na₃PO₄, K₂S, CaCl₂

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