Ccl, 189.86 g/mol. express your answer as a chemical formula.

Answer is: a chemical formula of the compound is C₄Cl₄.

CCl is empirical formula of the compound. Empirical formula gives the proportions of the elements present in a compound, so we know that proportion od carbon and chlorine is 1 : 1 (n(C) : n(Cl) = 1 : 1).

M(CCl) = Ar(C) + Ar(Cl) · g/mol.

M(CCl) = 12.0107 + 35.453 · g/mol.

M(CCl) = 47.4637 g/mol; molar mass of empirical formula.

M(compound) = 189.86 g/mol; molar mass of the compound.

M(compound) / M(CCl) = 189.86 g/mol / 47.4637 g/mol.

M(compound) / M(CCl) = 4; chemical formula of the compound have four carbon and four chlorine atoms.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

the atomic mass is the bottom number on the element.

-steel jelly