Using calories, calculate how much heat 32.0 g of water absorbs when it is heated from 25.0 octo 80.0 °c. how many joules is this?

Q = 1760 cal or 7356.8 J

Explanation:

The general expression to use to calculate heat is the following:

Q = m*Cp*ΔT (1)

Where:

Q = heat in cal or joules

m = mass of the compound.

Cp = specific heat of the compound

T: change in temperature (K) or T2 - T1

Now, the reported Cp for water is 1 cal/g °C and 4.18 J / g °C, we will use both to calculate the heat in calories and joules:

Using calories we have:

Q = 32 * 1 * (80 - 25)

Q = 1760 cal

This is the heat in calories.

Using joules we have:

Q = 32 * 4.18 * (80 - 25)

Q = 7356.8 J

This is the heat expressed in Joules.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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