Chemistry, 09.07.2019 17:30 eshavaggar

How many grams of naoh (mw = 40.0) are there in 500.0 ml of a 0.225 m naoh solution?

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Answer from: genny42

There are 4.5 grams of NaOH in 500.0 mL of a 0.225 M NaOH solution.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles by its molar mass. That is;mass (g) = no. of moles (mol) × molar mass (g/mol). However, the number of moles can be calculated by multiplying the molarity by the volume (in litres) of NaOH. no. of moles = molarity × volume no. of moles = 0.225M × 0.500Lno. of moles = 0.1125molMolar mass of NaOH = 23 + 1 + 16 = 40g/molmass of NaOH = 0.1125 × 40mass of NaOH = 4.5grams. Therefore, there are 4.5 grams of NaOH in 500.0 mL of a 0.225 M NaOH solution.

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Answer from: swordnewsnetwork

Given: Molar mass of NaOH=40 g/mol

Volume of NaOH solution=500 mL

Molarity of solution=0.225 M

Molarity of solution is defined as number of moles of solute in 1 L of solution. Thus,

$M=\frac{n}{V}$

Thus, to calculate the mass of NaOH, first calculate its number of moles by rearranging the above equation and putting values of volume and number of moles.

$n=M\times V=0.225 M(\frac{ mol/L}{1 M})\times 500 mL(\frac{10^{-3} L}{1 mL})=0.1125 mol$

Now, number of moles are related to mass as follows:

$n=\frac{m}{M}$

Here, M is molar mass

Rearranging and putting the values of number of moles and molar mass thus,

$m=n\times M=0.1125 mol\times 40 g/mol=4.5 g$

Therefore, mass of NaOH in 500 mL of 0.225 M NaOH solution is 4.5 g.

Answer from: Quest

i need mutiple choices

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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