Consider the gas-phase reaction, 2 so2 + o2 < => 2 so3, for which kp = 2 at a given temperature. if the mixture is analyzed and found to contain 2.2 bar of so2, 1.6 bar of o2 and 3.4 bar of so3, describe the situation:

The given reaction is

                    2 SO2 + O2 <=> 2 SO3, for which kp = 2 at a given temperature

Equilibrium constant = pSO3^2 / pSO2^2 X pO2

Q= (3.4)^2 / (2.2)^2 X 1.6 = 1.5

As Q< Kp

The reaction is not at equilibrium and reaction will go in forward direction

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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