What is the volume, in l, of 0.682 moles of o'what 2 gas having a temperature of 68.2 ºc and pressure of 5.82 atm?

We will use Ideal gas equation. PV=nRT where P= pressure(in atm)=5.82atm V=Volume=? n= moles of gases=0.682 R = gas constant= 0.0821L atm / mol K T = temperature= 68.2 C= 68.2 + 273.15 = 341.35 K V= nRT/ P= 0.682 X 0.0821 X 341.35/ 5.82 V= 3.284 L.  

i'm assuming that the correct answer is indeed the first one/ "a"..