Find the volume of 0.110 m hydrochloric acid necessary to react completely with 1.53 g al(oh)3.

Solution:

Molarity is defined as moles per volume.

So,

Since,We have 1.53g of the Aluminium complex which makes (moles =mass/mr) (1.53/78) = 0.019618 moles of aluminium complex The fundamental aspect to know is that one HCl will react with one of the OH molecules on the complex and so for each mole of Al(OH)3 you need 3HCl...  

The full reaction is:- Al(OH)3 + 3HCl - - > AlCl3 + 3H20. So 0.019618 X 3 = 0.0588 moles of HCl needed, and if we then plug that back into the first equation rearranged for volume we arrive at the answer which is 0.0588 moles / 0.110 = 0.534 dm3 or 534ml.

un recipient conține 6,4 moli de gaz. gazul hidrogen reprezintă 25% din totalul kilometrilor din container. în cazul în care presiunea totală este de 1.24 atm ceea ce este

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but